Halo! Today I have to make a python program that meets these conditions:

  1. Write a Python program that creates and print a dictionary that maps each element in a list to its corresponding frequency (how many times it occurs in the list).

  2. The test should be case-sensitive. Therefore, “A” should not be considered the same element as “a”.

I think for today, I’m just going to make it short. Yea…

So this is how you do it-

ele = ['a', 'a', 'b', 'c', 'a', 'b']

dict = {}

for i in ele:
    if i not in dict:
        dict[i] = 1
    else:
        
        
        dict[i] = dict[i] + 1

print(dict)

Output -

{'a': 3, 'b': 2, 'c': 1}

The end…

o-o