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In my other blog post ‘Binary to Decimal’, I realized what if I had put in a different number than 1 and 0. I tried putting a 2 and the code still worked. So I will be sharing an updated version, so that you can only put in either 1 or 0. Else there will be an error. # make a new function def bintodeci(num): reverse = len(num) -1 exp = 0 total = 0 for index in range(reverse, -1, -1): # if each number is either 0 or 1 else it'll print out an error. if num[index] in '01': total += int(num[index]) * (2**exp) exp += 1 else: print("Error: Invalid binary number") return None # return the value return total # In case I want to import it if __name__ == '__main__': print(f'The variable __name__ is {__name__}') answer = bintodeci("111") print(answer)

Hi, today I’m sharing a recursive funtion in python. Recursive in python means the ‘def’ function to call itself. The goal is to sum up the numbers to the number I want. For example, if I put in 3: 1 + 2 + 3 = 6 # def = makes a new function def sum(num): # if we have an 'if', we should also have an 'else'. if num == 0: return 0 else: return sum(num - 1) + num print(sum(2)) Outcome: ...

I’m sharing a program that converts binary to decimal in python. # make a new function def bintodeci(num): reverse = len(num) -1 exp = 0 total = 0 # range(start, stop, step) for digit in range(reverse, -1, -1): total += int(num[digit]) * (2**exp) exp += 1 # return the value return total answer = bintodeci("11") print(answer) sample output: 10 bai.